// ************************************************************************** //
//                                                                            //
//    eses                   eses                                             //
//   eses                     eses                                            //
//  eses    eseses  esesese    eses   Embedded Systems Group                  //
//  ese    ese  ese ese         ese                                           //
//  ese    eseseses eseseses    ese   Department of Computer Science          //
//  eses   eses          ese   eses                                           //
//   eses   eseses  eseseses  eses    University of Kaiserslautern            //
//    eses                   eses                                             //
//                                                                            //
// ************************************************************************** //
// The module below implements an algorithm for checking equality of binary   //
// signed digit numbers. It is based on the reduction x==y <-> x-y==0 and the //
// fact that 0 has uniquely representation. The subtraction can be done in    //
// depth O(1), but checking whether all digits are 0 requires time O(log(N)). //
// Note that the subtraction algorithm requires floor(B/2)+1 <= D < B which   //
// is not possible for B=2.                                                   //
// ************************************************************************** //

macro D = 3;     // digit set is -D,...,-1,0,1,...,D
macro B = 5;     // base of the radix numbers
macro N = 4;     // number of digits used for the addition

// macro to evaluate a signed digit number
macro sgnval(x,k) = sum(i=0..k-1) (x[i] * exp(B,i));


module SgnEqu([N]int{D+1} ?x,?y,bool eqq) {
    [N+1]int{2} t;      // transfer digits
    [N+1]int{D+1} s;    // sum digits of a-b

    // compute sum and transfer digits in parallel
    t[0] = 0;
    for(i=0..N-1)
        let(ds = x[i]-y[i]) {
        t[i+1] = (ds>=D?+1:(ds<=-D?-1:0));
        s[i] = ds + t[i] - t[i+1] * B;
        }
    s[N] = t[N];
    eqq = forall(i=0..N) (s[i]==0);
    assert(eqq <-> (sgnval(x,N) == sgnval(y,N)));
}